Question

解方程：(x/3)*3m = (1+20%)[(16/3)*m+(21/4)*2m] 求x

Answer 1

(x/3)*3m = (1+20%)[(16/3)*m+(21/4)*2m]

（1）当m =0时,x为任何实数.

（2）当m ≠0时,等式两侧都除以m得

x=(1+20%)[(16/3)+(21/4)*2] =6/5*(16/3+21/2)=6/5*(95/6)=19