Question

已知集合A={x|x2+x-6=0},B={x|ax-5=0},若A∪B=A,求实数a的值

Answer 1

a={x2+x-6=0}=> (x-2)(x+3)>=0

=> a是x=2b={ax-5=0}=> ax = 5

=> b是x = 5/a他要等于x 5/a a >= - 5/3他要等于x>=2

=> 5/a >=2

=> a = -5/3 , a