设An=(7n+1)nt(t≠0),则Bn=(4n+27)nt,
求得：an=14nt-6t,bn=8nt+23t,
所以a9=120t,b13=127t,即a9/b13=120/127
若等差数列an bn的前n项和An Bn满足An/Bn=（7n+1）/（4n+27）,求a9/b13
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