已知sina-cosa/sina=cosa=1/3,cos^4(π/3+a)-cos^4(π/6-a)=要详细的解题

2个回答

  • (sina-cosa)/(sina+cosa)=1/3

    ∴3sina-3cosa=sina+cosa

    ∴sina=2cosa

    ∴tana=2

    ∴sin2a=2sinacoa

    =2sinacosa/(sin²a+cos²a)

    =(2sina/cosa)/(sin²a/cos²a+1)

    =2tana/(tan²a+1)

    =4/5

    cos2a=(cos²a-sin²a)/(sin²a+cos²a)

    =(1-tan²a)/(1+tan²a)

    =-3/5

    ∴cos^4(π/3+a)-cos^4(π/6-a)

    =cos^4[π/2-(π/6-a)]-cos^4(π/6-a)

    =sin^4(π/6-a)-cos^4(π/6-a)

    =[sin²(π/6-a)+cos²(π/6-a)][sin²(π/6-a)-cos²(π/6-a)]

    =-[cos²(π/6-a)-sin²(π/6-a)]

    =-cos(π/3-2a)

    =sin2asinπ/3-cos2acosπ/3

    =4/5*√3/2+3/5*1/2

    =(4√3+3)/10