求下列函数的导数y = xcos(2x + π/2)sin(2x + π/2)
2个回答
y = xcos(2x + π/2)sin(2x + π/2)
y=1/2 Xsin(4x+π)
=-1/2Xsin(4x)
y'=-1/2(sin(4x)+4xcos(4x))
相关问题
sin2πx+cos2πx的周期 sin2πxcos2πx的周期
y=1+sinπx的周期~1+sinπ(X+2n)=1+sin(πX+2nπ)=1+sinπXcos2nπ+cosπXs
求导数 y=sin^2(2x+π/3)
函数y=sin平方(2x+π/3)的导数
求函数y=[sin2x+sin(2x+π/3)-cos1/2﹙π-4x﹚]/[cos2x+cos﹙2x+π/3﹚-sin
求下列函数的周期(1)y=2sin1/2x (2)y=cos(x+π/3) (3)y=2sin(2/3x-π/4)
y=2sin^2(2x+π/3)的导数怎么求
求下列函数的值域 (1)y=3sin(2x+π/2)-1 (x∈[-π/4,π/3]) (2)y=(cosx)^2-3c
求函数y=sin(1/2x+π/3),x∈[-2π,2π]的单调递增区间
y=sin^2(2x+π/3)的导数和y=(sin(2x+π/3))^2的导数应该各怎么求啊?我都晕了、