x/(x+1) -1/x=1; x/x-1+(2/1-x)=2这两道题怎么算,拜托,帮帮忙,在线等
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x/(x+1)=(x+1)/x,所以(x+1)^2=x^2,移项,平方差,解得x=-1/2
x/(x-1)=-2x/(1-x),所以x/(x-1)=0,所以x=0
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