换元思想
设x^2+x/2=y
-(3/2)
2y-4=---------
y
2y^2-4y=-(3/2)
y^2-2y=-(3/4)
(y-1)^2=1/4
y-1=(+-)1/2
y1=3/2 y2=1/2
x^2+x/2=3/2 x^2+x/2=1/2
(x+1/4)^2=25/16 (x+1/4)^2=9/16
x1=1 x2=-3/2 x3=1/2 x4=-1 经检验x1=1 x2=-3/2 x3=1/2 x4=-1 是分式方程的根
换元思想
设x^2+x/2=y
-(3/2)
2y-4=---------
y
2y^2-4y=-(3/2)
y^2-2y=-(3/4)
(y-1)^2=1/4
y-1=(+-)1/2
y1=3/2 y2=1/2
x^2+x/2=3/2 x^2+x/2=1/2
(x+1/4)^2=25/16 (x+1/4)^2=9/16
x1=1 x2=-3/2 x3=1/2 x4=-1 经检验x1=1 x2=-3/2 x3=1/2 x4=-1 是分式方程的根