2x^2+14x+24分之x^2+16+8x,其中x=-6
=(x²+8x+16))/2(x²+7x+12)
=(x+4)²/2(x+3)(x+4)
=(x+4)/2(x+3)
=(-6+4)/2(-6+3)
=-2/(-6)
=1/3
当x=3,y=-2,求x^2-(y-1)^2分之x^2-y^2乘以x^2+2yx+y^2分之（x-y)^2-1除以x^2+xy-x分之x^2-xy的
=x²-(x²-y²)/(y-1)²*(x-y)²/(x²+2xy+y²)-1/(x²+xy)-(x²-xy)/x
这个题目看不懂
分子和分母分不清