Question

3道因式分解速求答案需要过程~(1)x^3+3x^2-4(2)(x+y)^2+4(x-y)^2-4(x^2-y^2)(3

Answer 1

(1)x^3+3x^2-4

=x^3+2x^2+x^2-4

=x^2(x+2)+(x-2)(x+2)

=(x^2+x-2)(x+2)

=(x-1)(x+2)^2

(2)(x+y)^2+4(x-y)^2-4(x^2-y^2)

=(x+y)^2+^2-4(x-y) (x+y)

=^2

=(3x-y)^2

(3)x^4-2X^2+5x-4

=x^4-X^2-x^2+5x-4

=x^2(X^2-1)-(x-1)(x-4)

=x^2(X-1)(x+1)-(x-1)(x-4)

=(x-1)(x^3+x^2-x+4)