∵ a ² + a - 1 = 0
∴ a ² + a = 1
∴ a ³ + 2 a ² + 2010
= a ³ + a ² + a ² + 2010
= a(a ² + a)+ a ² + 2010
= a + a ² + 2010
= 1 + 2010
= 2011
∵ a ² + a - 1 = 0
∴ a ² + a = 1
∴ a ³ + 2 a ² + 2010
= a ³ + a ² + a ² + 2010
= a(a ² + a)+ a ² + 2010
= a + a ² + 2010
= 1 + 2010
= 2011