Question

1/5+(5+7又4/5x3又1/3)x3/31十42又14/15除以7 简算

Answer 1

1/5+(5+7又4/5×3又1/3)×3/31十42又14/15÷7

=1/5+(5+26)×3/31+(42+14/15)×1/7

=1/5+31×3/31+6+2/15

=1/5+3+6+2/15

=9又1/3