Question

（A除以x+2）+（B除以x-3）=5x除以(x+2)(x-3),求A,B的值

Answer 1

A(x-3)/[(x+2)(x-3)]+B(x+2)/[(x+2)(x-3)]=5x/[(x+2)(x-3)]

(Ax-3A+Bx+2B)/[(x+2)(x-3)]=5x/[(x+2)(x-3)]

[(A+B)x+(-3A+2B)]/[(x+2)(x-3)]=5x/[(x+2)(x-3)]

A+B=5 且 -3A+2B=0

A=2,B=3