通项an=n+(1/2)^nrn前6项之和=1+2+3+4+5+6+(1/2)^1+(1/2)^2+(1/2)^3+(1/2)^4+(1/2)^5+(1/2)^6rn(1+6)x6/2 +1/2[1-(1/2)^6]/(1-1/2)rn=21+63/64
通项an=n+(1/2)^nrn前6项之和=1+2+3+4+5+6+(1/2)^1+(1/2)^2+(1/2)^3+(1/2)^4+(1/2)^5+(1/2)^6rn(1+6)x6/2 +1/2[1-(1/2)^6]/(1-1/2)rn=21+63/64