已知a=-3,b=2.求代数式(1/a+1/b)+a的2次方+2ab+b的2次方/a+b
=(a+b)/(ab)+(a+b)²/(a+b)
=(a+b)/(ab)+(a+b)
=(a+b)(1/(ab)+1)
=(-3+2)(1/(-3×2)+1)
=-1×(5/6)
=-5/6;
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已知a=-3,b=2.求代数式(1/a+1/b)+a的2次方+2ab+b的2次方/a+b
=(a+b)/(ab)+(a+b)²/(a+b)
=(a+b)/(ab)+(a+b)
=(a+b)(1/(ab)+1)
=(-3+2)(1/(-3×2)+1)
=-1×(5/6)
=-5/6;
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,