a^5=b^4,c^3=d^2,a-c=65,求b-d.
设x^4=a x^5=b
y^2=c y^3=d (x,y均为正整数)
则x^4-y^2=65
(x^2+y)(x^2-y)=65
易知x^2+y=13 x^2-y=5
(分解质因数,如果x^2+y=65,x^2-y=1,则x非整数)
解得x=3 y=4
所以b=x^5=243 d=y^3=64
b-d=179
a^5=b^4,c^3=d^2,a-c=65,求b-d.
设x^4=a x^5=b
y^2=c y^3=d (x,y均为正整数)
则x^4-y^2=65
(x^2+y)(x^2-y)=65
易知x^2+y=13 x^2-y=5
(分解质因数,如果x^2+y=65,x^2-y=1,则x非整数)
解得x=3 y=4
所以b=x^5=243 d=y^3=64
b-d=179