左边
=(x+c/x-c)^x
=[1+2c/(x-c)]^x
=[1+2c/(x-c)]^[(x-c)/2c]*2cx/(x-c)
x趋于正无穷时 原式 = e^[2cx/(x-c)] = e^2c
右边
=(1/2)∫tde^2t
=(1/2)[te^2t|(负无穷到C) - ∫(负无穷到C)e^2tdt]
=(C/2 - 1/4)e^2c
所以C/2 - 1/4 = 1
C = 5/2
左边
=(x+c/x-c)^x
=[1+2c/(x-c)]^x
=[1+2c/(x-c)]^[(x-c)/2c]*2cx/(x-c)
x趋于正无穷时 原式 = e^[2cx/(x-c)] = e^2c
右边
=(1/2)∫tde^2t
=(1/2)[te^2t|(负无穷到C) - ∫(负无穷到C)e^2tdt]
=(C/2 - 1/4)e^2c
所以C/2 - 1/4 = 1
C = 5/2