C(n+1 7) -C(n 7)=C(n 8)
(n+1)n(n-1)...(n-5)/(1×2×...×7)- n(n-1)...(n-6)/(1×2×...×7)=n(n-1)...(n-7)/(1×2×...×8)
等式两边同乘以(1×2×...×8)/[n(n-1)...(n-5)]
8(n+1)-8(n-6)=(n-6)(n-7)
整理,得
n²-13n-14=0
(n+1)(n-14)=0
n=-1(舍去)或n=14
n=14
C(n+1 7) -C(n 7)=C(n 8)
(n+1)n(n-1)...(n-5)/(1×2×...×7)- n(n-1)...(n-6)/(1×2×...×7)=n(n-1)...(n-7)/(1×2×...×8)
等式两边同乘以(1×2×...×8)/[n(n-1)...(n-5)]
8(n+1)-8(n-6)=(n-6)(n-7)
整理,得
n²-13n-14=0
(n+1)(n-14)=0
n=-1(舍去)或n=14
n=14