25(x-2y)³+4(2y-x)
=(x-2y)[25(x-2y)²-4]
=(x-2y)[5(x-2y)+2)][5(x-2y)-2]
=(x-2y)(5x-10y+2)(5x-10y-2)
分解因式：25（x-2y）3次方+4（2y-x)
25(x-2y)³+4(2y-x)
=(x-2y)[25(x-2y)²-4]
=(x-2y)[5(x-2y)+2)][5(x-2y)-2]
=(x-2y)(5x-10y+2)(5x-10y-2)