Question

欧姆定律计算练习题3如图所示,电阻R的电阻为10Ω

Answer 1

1:设点源电压 UV 则 U/(15 + 60) = 0.2 则 U = 15(V)

则点流为1.2A时 总电阻 R= 15/1.2 =12.5

(欧姆)电阻变小,采用并联 R2*15/(R2 + 15) =12.5

R2 = 75(欧姆)

2.电阻串联,R1电流与R2电流相等;I = V1/R1 =V2/R2

I = 2 / 4 =0.5 (A)

R2 = (6-2)/I = 4/0.5 = 8(欧姆)