Question

A=(3/2)*(5/4)*(7/6)*(9/8).(2005/2004) 证明"31

Answer 1

3/2>4/3

5/4>6/5

.

2005/2004>2006/2005

(3/2)*(5/4)*.(2005/2004)>(4/3)*(6/5)*.(2006/2005)

[(3/2)*(5/4)*.(2005/2004)]^2>(3/2)*(5/4)*.(2005/2004)*(4/3)*(6/5)*.(2006/2005)=3/2*4/3*5/4*6/5*...*2005/2004*2006/2005=2006/2=1003

即A^2>1003,所以A>根号下1003>31

同理A^2