"(X/X-1)^2＋6＝5"应该是"(x/x-1)^2+6=5(x/x-1)"吧
设x/x-1=t 于是 t^2+6=5t t^2-5t+6=0
(t-2)(t-3)=0 t=2 或3
x/(x-1)=2 => x=2
x/(x-1)=3 => x=3/2
方程(x/x-1)^2+6=5(x/x-1)的整数解是2
求方程(X/X-1)的平方＋6＝5的整数解
"(X/X-1)^2＋6＝5"应该是"(x/x-1)^2+6=5(x/x-1)"吧
设x/x-1=t 于是 t^2+6=5t t^2-5t+6=0
(t-2)(t-3)=0 t=2 或3
x/(x-1)=2 => x=2
x/(x-1)=3 => x=3/2
方程(x/x-1)^2+6=5(x/x-1)的整数解是2