(1) (x+1)^2+(y-3)^2 = 16
x+1 = 4cosθ x=4cosθ-1
y-3 = 4sinθ y=4sinθ+3
(2)点P(x,y)到直线x+Y-2=O的距离d
d=(4cosθ-1+4sinθ+3-2)/根号(1+1)
d=2根号2(sinθ+cosθ)
d=4sin(θ+π/4)
(1) (x+1)^2+(y-3)^2 = 16
x+1 = 4cosθ x=4cosθ-1
y-3 = 4sinθ y=4sinθ+3
(2)点P(x,y)到直线x+Y-2=O的距离d
d=(4cosθ-1+4sinθ+3-2)/根号(1+1)
d=2根号2(sinθ+cosθ)
d=4sin(θ+π/4)