Question

已知3a^2+2ab-2b^2=0,求a÷b-b÷a-(a^2+b^2)÷ab的值.

Answer 1

已知3a^2+2ab-2b^2=0,

a = -2±根号(4+24) / 6

= (-1±根号7)b / 3

b/a = 3 /(-1±根号7)

a÷b-b÷a-(a^2+b^2)÷ab

= a/b - b/a - a/b - b/a

= -2b/a

= -6 /(-1±根号7)

= 6 /(1 ±根号7)

= 6(1 ±根号7) / (-6)

= (-1 ±根号7)

式子 值为 -1 +根号7 或者 -1 -根号7