Question

请帮我换算一个方程0=(1-B3/B2)*(B4+B5+B8)+(B3/B2)*((B7+B5+B8)*B9*X-(B7

Answer 1

这样化简：

0=(1-B3/B2)*(B4+B5+B8)+(B3/B2)*((B7+B5+B8)*B9*X-(B7-B5)*(1-X))

0=(1-B3/B2)*(B4+B5+B8)+(B3/B2)*((B7+B5+B8)*B9*X-(B7-B5)+(B7-B5)*X)

-(1-B3/B2)*(B4+B5+B8)=(B3/B2)*( ((B7+B5+B8)*B9+B7-B5)*X-(B7-B5))

-(1-B3/B2)*(B4+B5+B8)*B2/B3= ((B7+B5+B8)*B9+B7-B5)*X-(B7-B5)

B7-B5-(1-B3/B2)*(B4+B5+B8)*B2/B3= ((B7+B5+B8)*B9+B7-B5)*X

(B7-B5-(1-B3/B2)*(B4+B5+B8)*B2/B3)/ ((B7+B5+B8)*B9+B7-B5)=X

即X=(B7-B5-(1-B3/B2)*(B4+B5+B8)*B2/B3)/ ((B7+B5+B8)*B9+B7-B5)