第一题:( x + y - 2xy )(x + y - 2 )+(xy-1)²

1个回答

  • 第一题:(x + y - 2xy)(x + y - 2 )+(xy-1)²

    =(x+y)^2-2xy(x+y)-2(x+y)+4xy+(xy)^2-2xy+1

    =(x+y)^2-2(xy+1)(x+y)+(xy+1)^2 (注:这里设x+y=a,xy+1=b,可能容易理解些)

    =[(x+y)-(xy+1)]^2

    =[(x-1)(y-1)]^2

    =(x-1)^2*(y-1)^2

    第二题:(x +1)(x+2)(x+3)(x+6)+x²

    = [(x+1)(x+6)][(x+2)(x+3)]+x^2

    =(x^2+6+7x)(x^2+6+5x)+x^2

    =(x^2+6)^2+12x(x^2+6)+35x^2+x^2

    =(x^2+6)^2+2*6x(x^2+6)+(6x)^2

    =(x^2+6+6x)^2

    =(x^2+6x+6)^2

    第三题:9x²-15xy-6y²=3(3x²-5xy-2y²)

    =3(3x+y)(x-2y)

    =3*2007/3*8/2007

    =8