Question

2/(2x-3)+6/(6x+7)=1/(x+1)+3/(3x-4)求过程

Answer 1

2/(2x-3)+6/(6x+7)=1/(x+1)+3/(3x-4)

(4 (-1 + 6 x))/((-3 + 2 x) (7 + 6 x)) = (-1 + 6 x)/((1 + x) (-4 + 3 x))

(-1 + 6 x)/(84 + 37 x - 107 x^2 - 24 x^3 + 36 x^4) =0

6 x-1=0

x=1/6