4x的平方-20x+25=16
4x²-20x+25=16
(2x-5)²=16
(2x-5)²-16=0
(2x-5+4)(2x-5-4)=0
(2x-1)(2x-9)=0
x1=1/2
x2=9/2
4x的平方-20x+25=16,怎么解
4x的平方-20x+25=16
4x²-20x+25=16
(2x-5)²=16
(2x-5)²-16=0
(2x-5+4)(2x-5-4)=0
(2x-1)(2x-9)=0
x1=1/2
x2=9/2