a^2+b^2+c^2+2(a+b+c)+3=0
a^2+2a+1+b^2+2b+1+c^2+2c+1=0
(a+1)^2+(b+2)^2+(C+1)^2=0
因为(a+1)^2>=0 (b+2)^2>=0 (C+1)^2>=0
所以(a+1)^2=(b+2)^2=(C+1)^2=0
a=b=c=-1
a^3+b^3+c^3-3abc=-1-1-1+3=0
a^2+b^2+c^2+2(a+b+c)+3=0
a^2+2a+1+b^2+2b+1+c^2+2c+1=0
(a+1)^2+(b+2)^2+(C+1)^2=0
因为(a+1)^2>=0 (b+2)^2>=0 (C+1)^2>=0
所以(a+1)^2=(b+2)^2=(C+1)^2=0
a=b=c=-1
a^3+b^3+c^3-3abc=-1-1-1+3=0