Question

5.6克铁粉和50克稀硫酸恰好完全反应,求反应后所得溶液的质量,溶质的质量和溶剂的质量

Answer 1

Fe+ H2SO4= FeSO4+ H25.6g x y z------------------------------------------------------------56g/mol 98g/mol 152g/mol 2g/mol算出x=9.8gy=15.2gz=0.2g反应后所得溶液的质量=5.6g+50g-0.2g=55.4g溶质的质量=15.2g溶剂的质量=55.4g-15.2g=40.2g