数学初一整式的化简题. -(3a²-1-3a)-4(a-1+a²)

1个回答

  • -(3a²-1-3a)-4(a-1+a²)

    =-3a²+1+3a-4a+4-4a²

    =(-3a²-4a²)+(1+4)+(3a-4a)

    =-7a²+5-a

    3(-4b²+3a²)-2(a²-2b²)-7(b²-2a²)

    =-12b²+9a²-2a²+4b²-7b²+14a²

    =(-12b²+4b²+14a²)+(9a²-2a²+14a²)

    =6b²+21a²

    -x²+3xy-1/2-(-1/2x²+4xy-3/2y²)

    =-x²+3xy-1/2+1/2x²-4xy+3/2y²

    =(-x²+1/2x²)+(3xy-4xy)-1/2

    =-1/2x²-xy-1/2

    4(x-1)-2(x²+1)-1/2(4x²-2x)

    =4x-1-2x²-2-2x²+1x

    =(4x-2x)-(2x²+2x²)-(1+2)

    =2x-4x²-3

    当x=-3时,原式=2×(-3)-4×(-3)²-3

    =-6-36-3

    =-45