是x1的2次方 5(x2)的2次方=10 来算以x2y1-x1y2=5.(1) x1y1 5x2y2=15.(2) 列方程组一,(1)*5x2 (2)*x1 可得(5(x2)^2 (x1)^2)y
若x1^2+5x2^2=10,x2y1-x1y2=5,x1y1+5x2y2=15,求y1^2+5y2^2
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