Question

函数f(x)是以派/2为最小正周期的函数,且f(派/3)=1,求f(17派/6)的值

Answer 1

函数f(x)是以π/2为最小正周期的函数f(x+π/2)=f(x)

f(17π/6)=f(5π/6+π/2*4)=f(5π/6）=f(π/3+π/2)=(fπ/3)

因为f(π/3)=1,所以f(17π/6)=1