因式分解(x+1)(x+3)(x+5)(x+7)- - 知识问答

因式分解(x+1)(x+3)(x+5)(x+7)-12

1个回答

=[(x+1)(x+7)][(x+3)(x+5)]-12
=(x²+8x+7)(x²+8x+15)-12
=(x²+8x)²+22(x²+8x)+105-12
=(x²+8x)²+22(x²+8x)+93
=【x²+8x+11】²-28
=(x²+8x+11+2√7)(x²+8x+11-2√7)

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