Question

(1/x-1)+(2/6y-3)=1,(1/2x-2)-(1/2y-1)=0,解x、y.

Answer 1

1/(x-1)+1/(6y-3)=1

1/(2x-2)-1/(2y-1)=0

令a=1/(2x-2),b=1/(6y-3)

则1/(x-1)=2a,1/(2y-1)=3b

所以2a+b=1

a-3b=0

a=3b

6b+b=1

b=1/7,a=3/7

1/(2x-2)=3/7

6x-6=7

x=13/6

1/(6y-3)=1/7

6y-3=7

y=5/3

x=13/6

y=5/3

是不是这样的啊~你打错的哦~