首先根据分母可知x不等于1、-2.
两边同乘以(x-1)(x+2),可得
x(x+2) - (x-1)(x+2) = 3(x-1)
x²+2x-(x²+x-2) = 3x-3
x²+2x-x²-x+2 = 3x-3
x+2 = 3x -3
解得x = 5/2
首先根据分母可知x不等于1、-2.
两边同乘以(x-1)(x+2),可得
x(x+2) - (x-1)(x+2) = 3(x-1)
x²+2x-(x²+x-2) = 3x-3
x²+2x-x²-x+2 = 3x-3
x+2 = 3x -3
解得x = 5/2