Question

一道复数的计算题 化简 (2-i)^10/(1-2i)^8=

Answer 1

(1-2i)^5(3+4i)/(2-i)^5

=[(1-2i)/(2-i)]^5*(3+4i)

=[(-i)(2-i)/(2-i)]^5(3+4i)

=[-i]^5(3+4i)

=-i*(3+4i)

=4-3i