设(a-b)/x=(b-c)/y=(c-a)/z=k,k不=0.
x=(a-b)/k,y=(b-c)/k,z=(c-a)/k
x+y+z=（a-b)/k+（b-c)/k+(c-a)/k
=0/k
=0
若a-b/x=b-c/y=c-a/z不等于0则x+y+z=
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