Question

分解因式:(x^2+2x-3)(x^2-4)-60

Answer 1

(x^2+2x-3)(x^2-4)-60

=(x+3)(x-2)(x+2)(x-1)-60

=(x^2+x-6)(x^2+x-2)-60

=(x^2+x)^2-8(x^2+x)-48

=(x^2+x-12)(x^2+x+4)

=(x^2+x+4)(x+4)(x-3)

(a^5-a^4b-a^4)+(a-b-1)

=(a^4+1)(a-b-1)

a-b=1,2a-3b=1;a=2,b=1

a^3+b^3=9