Question

设函数f(x)=Asin(πx+m)+Bcos(πx+k),若f(2009)=1,则f(2010)=

Answer 1

f(x)=Asin(πx+m)+Bcos(πx+k)

f(2009)=Asin(π+m)+Bcos(π+k)=-Asinm-Bcosk=1

f(2010)=Asin(m)+Bcos(k)=-1

请指教呀!