几道初三数学题,大神们求解QAQ

5个回答

  • (1)a³+1=(a+1)(a²-a+1)

    (2)b²+c²+2ab+2ac+2bc=(b+c)²+2a(b+c)=(b+c)(b+c+2a)

    (3)3x²+5xy-2y²+x+9y-4=(3x-y)(x+2y)+x+9y-4

    =(3x-y)(x+2y)-(3x-y)+4x+8y-4

    =(3x-y)(x+2y-1)+4(x+2y-1)

    =(3x-y+4)(x+2y-1)

    (4)x+y/x-y=x²-y²/(x-y)²=2xy/x²+y²+x²-y²=2xy/2x²=y/x

    (5)因为(x²+1/x²)=(x+1/x)²-2*x*1/x=(x+1/x)²-2

    所以设a=x+1/x

    2(a²-2)-3a-1=0

    a=-1(舍)或5/2

    所以x=5±√17/4

    (6)由根号下-a分之1知-1/a≥0

    所以a≤0

    所以原式=√[-a*(-a)*(-1/a)]=√-a