Question

用因式分解的方法.2x²-2根号3x=1

Answer 1

2x²-2根号3x-1=0

2x²-2√3x-1=0

x²-√3x-1/2=0

-1=[(√3+2√5)/√2]*[(√3-2√5)/√2]

所以

[x-(√3+2√5)/√2]*[x(√3-2√5)/√2]=0