求不定积分(*¯︶¯*),

1个回答

  • 设 x = 2sint,则 dx = 2cost*dt

    ∫x^2*√(4-x^2) *dx

    =∫(2sint)^2 * (2cost) * (2cost)*dt

    =16*∫(sint)^2 * (cost)^2 *dt

    =4*∫(2sint*cost)^2 *dt

    =4*∫(sin2t)^2 *dt

    =2*∫[2*(sin2t)^2] *dt

    =2*∫[1 - cos4t] *dt

    =2∫dt - 2∫cos4t*dt

    =2t - 1/2*∫cos4t*d(4t)

    =2t - 1/2*sin4t + C

    =2t - sin2t *cos2t + C

    =2t - 2sint*cost*[1 - 2(sint)^2] + C

    =2arcsin(x/2) - x/2*√(4 - x^2).*(1-x^2/2) + C