根的判别式(2k+1)^2-4k^20 = k-1/4
k不等于0
设f(x)=kx2+(2k+1)x+k,则k0时f(1)=k+2k+1+k0,不成立
k0时f(1)=k+2k+1+k0 = k-1/4
综上,-1/4k0