m[2sin(πx/4-3π/4)+8-2sin(

m[2sin(πx/4-3π/4)+8-2sin(xπ/4-π/4)-6] 那个n是派,不知道能不能显示.

1个回答

2sin（πx/4-π/4）+6＜2sin（πx/4-3π/4）+8
y=sin(π/4+x/2)sin(π/4-x/2) =sin(π/4+x/2)sin[π/2-(π/4+x/2)]
求证:sin(π/4+x)/sin(π/4-x)+cos(π/4+x)/(π/4-x)=2/cos2x
2sin(x+π/4)sin(x-π/4)=?
为什么sin11π/3=sin（4π-π/3）=－sinπ/3=－根号3/2,sin（4π-π/3）=－sinπ/3我不
y=4sin(πx/8+π/4-π)怎样变成y=-4sin(πx/8+π/4）过程~
函数f(x)=sin(2x+π\4)+cos(2x+π\4)=根号2sin(2x+π/2) 老师这题还是不能理解,带入
sin(x-π/4 + π/2 )=-cos(x+π/4)
f(x)=1-2sin^2(x+π/8)+2sin(x+π/8)*cos(x+π/8)=cos(2x+π/4)+sin(
fx=1-2sin^2(x+π/4)+2sin(x+π/8)cos(x+π/8)