小题1:(1)△ABC∽△ADE, △ABD∽△ACE(2分)
小题2:(2)①证△ABC∽△ADE
∵∠BAD=∠CAE∴∠BAD+∠DAC=∠CAE+∠DAC,
即∠BAC=∠DAE又∵∠ABC=∠ADE ∴△ABC∽△ADE(4分)
②证△ABD∽△ACE
∵△ABC∽△ADE,∴
又∵∠BAD=∠CAE ∴△ABD∽△ACE(6分)
略
小题1:(1)△ABC∽△ADE, △ABD∽△ACE(2分)
小题2:(2)①证△ABC∽△ADE
∵∠BAD=∠CAE∴∠BAD+∠DAC=∠CAE+∠DAC,
即∠BAC=∠DAE又∵∠ABC=∠ADE ∴△ABC∽△ADE(4分)
②证△ABD∽△ACE
∵△ABC∽△ADE,∴
又∵∠BAD=∠CAE ∴△ABD∽△ACE(6分)
略