Question

（x-3）^5=ax^5+bx^4+cx^3+dx^2+ex+f 问：a+b+c+d+e+f=?a-b+c-d+e=?请

Answer 1

x=1时,a+b+c+d+e+f=（1-3）^5=-32;

x=-1时,-(a-b+c-d+e-f)=(-1-3)^5=-1024,得a-b+c-d+e-f=1024

x=0时,f=-243,所以a-b+c-d+e=1024+f=781