Question

已知m²+2n²+2p²-2mn-2np-6p+9=0,求m分之n²p

Answer 1

m²+2n²+2p²-2mn-2np-6p+9=0m²-2mn+n²+p²-6p+9+n²-2np+p²=0(m-n)^2+(p-3)^2+(n-p)^2=0(m-n)^2=0,m=n(p-3)^2=0,p=3(n-p)^2=0,n=p所以m=n=p=3m分之n²p=27除以3=9