Question

方程 5/(x-2)+3/(2-x)=2 计算 (3x-2)/(x^2-x-2)+[1-1/(x+1)]/[1+1/(x

Answer 1

方程 5/(x-2)+3/(2-x)=2

两边乘以x-2得

5-3=2(x-2)

∴x=1

经检验：x=1是方程的解

∴方程的解是x=1

计算 (3x-2)/(x^2-x-2)+[1-1/(x+1)]/[1+1/(x-1)]

=(3x-2)/[(x-2)(x+1)]+[x/(x+1)]/[x/(x-1)]

=(3x-2(/[(x-2)(x+1)]+(x-1)/(x+1)

=[(3x-2)+(x-2)(x-1)]/[(x-2)(x+1)]

=x²/(x²-x-2)