1
题目不完整;
2
√2=1.414...
所以5+√2的整数部分为6,x=6;
5+√2=x+y,
y=5+√2-x=5+√2-6=-1+√2;
x/y=6/(-1+√2)=6(1+√2)/[(-1+√2)(1+√2)]=(6+6√2)/[(√2)²-1²]=6+6√2.
1
题目不完整;
2
√2=1.414...
所以5+√2的整数部分为6,x=6;
5+√2=x+y,
y=5+√2-x=5+√2-6=-1+√2;
x/y=6/(-1+√2)=6(1+√2)/[(-1+√2)(1+√2)]=(6+6√2)/[(√2)²-1²]=6+6√2.