2∧x+2 ∧-x
=2∧log4 3+2∧-log4 3
=2∧1/2log2 3+2 ∧-1/2log2 3
=(2∧log2 3)∧1/2+(2∧log2 3)∧-1/2
=3∧1/2+3∧-1/2
=√ ̄3+√ ̄(1/3)
=√ ̄3+(√ ̄3)/3
=(4√ ̄3)/3
2∧x+2 ∧-x
=2∧log4 3+2∧-log4 3
=2∧1/2log2 3+2 ∧-1/2log2 3
=(2∧log2 3)∧1/2+(2∧log2 3)∧-1/2
=3∧1/2+3∧-1/2
=√ ̄3+√ ̄(1/3)
=√ ̄3+(√ ̄3)/3
=(4√ ̄3)/3